-8h^2+24h+32=0

Solution for -8h^2+24h+32=0 equation:

-8h^2+24h+32=0

a = -8; b = 24; c = +32;
Δ = b2-4ac
Δ = 242-4·(-8)·32
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-40}{2*-8}=\frac{-64}{-16}
=+4
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+40}{2*-8}=\frac{16}{-16}
=-1
$